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Last Updated: October 15, 2026
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Consider the following pseudo code, where and are positive integers. begin q := 0 r := x while r ≥ y do begin r := r - y q := q + 1 ... What is the output of the following C code? Assume that the address of x is 2000 (in decimal) and an integer requires four ... include stdio.h int f1(void); int f2(void); int f3(void); int x=10; int main() { int x=1; x += f1() + f2 () + f3() + f2(); printf("%d", x); return 0; } ...
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